2013国赛数模C题第二问扭曲

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we get 3 slopes.预测15层楼在时间上是线性的,拟合后会得到一个三维方程 t floorincluding the top of the tower,after all,st floor,the third floor is from 11st floor to 14s5st floor,the second floor is from 6st floor to 10traight lines,the first part is from 1st floor to se years can be divided in to 3 parts of Sloping sse values,we find that those fitting curves in thoe as the angle of the tilt .After calculating thoof the centers of 13 floors and the horizontal linWe consider the angle between the fitting curve ),第一段为1-5层,第二段为6-10层,第三段为11-14(包括塔尖),即最终得到3个倾斜的斜率。过对中心拟合的计算和观察我们发现这四个年份的倾斜应该分为三段倾斜直线来拟合(这样基本可以保证误差最小 我们认为倾斜方向就是13层每层的中心拟合后的斜线与水平面的夹角。通-0.001705758-0.0017182860.00024829668519860.0107047240.0123219160.0133378630.013334137-0.001687675-0.0017705760.00356427393-0.0026225919960.0106943230.012327270.023448085-0.001515942-0.002195775-0.0024168-0.002436809-0.00264278420090.0211552180.021159140.023479128-0.001557151-0.002180360.009835995angle891011121320110.0191407270.0164940550.0188041030.01974718795420.019751780.00984409519860.01820059219960.0181923140.0191502650.0164939590.010.0092740110.0107189230.029216820.0119044198230.01189328320090.0102122750.01085380390.0108571430.0092636760.0107143850.029237ed dataangle23456720110.0102096tal angle is ;Matlab FigureComput;we can calculate the total the same way .The tockwise,and sin,when is very small and close to 0ctor cross product ,the value is positive when clo the angle between the two vectors.,””means the vevector from to a specific corner , is from to ,isloor as ,the center of floor above as , is the .The ula is that we set the center of one fter of the floor above to the corresponding cornerecific corner and the other vector is from the cene vector is from the center of one floor to one sptle angle is the angle between the two vectors ,onon to uate the torsion resistance and each litle which is the sum of eight angles as the criterithe angle of twist the way we the consider the ang个角相加即可。Matlab示意图为Our to calculate the 的时候可近似等于,总的扭转角即为求出剩下七个点(B、C、D、E、F、G、H)对应的、、、、、、,八平移到同一点有、,则、的扭转角即为、对应的扭转角,设为,有内为向量乘以顺时针为正,当sin很小二层中心为,第一层对的某一角的对应点为得到向量第二层对应的对的某一角的对应点为得到向量,将向量、的、角度,类似的两层之间可以得到八个夹角,将该八个角加起来即为总的扭曲度。计算式为若第一层中点为第 我们计算扭曲的方法为计算一层的中心到某一角与其上面一层的中心到对应的该一角的向量之间的夹角作为
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